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    <script>
        // 利用递归函数求1~n的阶乘 1 * 2 * 3 * 4 * ..n
        function fn(n) {
            if (n == 1) {
                return 1;
            }
            return n * fn(n - 1);
        }
        console.log(fn(3));
        console.log(fn(4));
        // 详细思路 假如用户输入的是3
        //return  3 * fn(2)
        //return  3 * (2 * fn(1))
        //return  3 * (2 * 1)
        //return  3 * (2)
        //return  6
    </script>
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